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2a^2-56a+384=0
a = 2; b = -56; c = +384;
Δ = b2-4ac
Δ = -562-4·2·384
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-8}{2*2}=\frac{48}{4} =12 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+8}{2*2}=\frac{64}{4} =16 $
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